(X+4)^2=3x+40

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Solution for (X+4)^2=3x+40 equation: 



(X+4)^2=3X+40

We move all terms to the left:

(X+4)^2-(3X+40)=0

We get rid of parentheses

(X+4)^2-3X-40=0

We add all the numbers together, and all the variables

-3X+(X+4)^2-40=0

We move all terms containing X to the left, all other terms to the right

-3X+(X+4)^2=40

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